Elegantly handle numlock when typing Æ and æ

main
Ashelyn Dawn 3 years ago
parent 32f4cb6a51
commit 90a7193bf3

@ -61,7 +61,7 @@ const uint16_t PROGMEM keymaps[][MATRIX_ROWS][MATRIX_COLS] = {
_______, RGB_SPD, RGB_VAI, RGB_SPI, RGB_HUI, TG(_TL), _______, U_T_AUTO,U_T_AGCR,_______, KC_PSCR, KC_SLCK, KC_PAUS, _______, KC_DEL, \
_______, RGB_RMOD,RGB_VAD, RGB_MOD, RGB_HUD, TG(_GL), TG(_UL), _______, _______, G(KC_L), _______, _______, RCTL(KC_ENT), KC_VOLU, \
_______, RGB_TOG, _______, _______, _______, MD_BOOT, NK_TOGG, DBG_TOG, _______, _______, RCTL(KC_SLSH), _______, KC_PGUP, KC_VOLD, \
_______, _______, _______, KC_MEDIA_PLAY_PAUSE, _______, MO(_FL), RCTL(KC_LEFT), KC_PGDN, RCTL(KC_RGHT) \
KC_NLCK, _______, _______, KC_MEDIA_PLAY_PAUSE, _______, MO(_FL), RCTL(KC_LEFT), KC_PGDN, RCTL(KC_RGHT) \
),
[_TALI_LAYER] = LAYOUT(
XXXXXXX, XXXXXXX, XXXXXXX, XXXXXXX, XXXXXXX, XXXXXXX, XXXXXXX, XXXXXXX, XXXXXXX, XXXXXXX, XXXXXXX, XXXXXXX, XXXXXXX, XXXXXXX, XXXXXXX, \
@ -361,24 +361,46 @@ bool process_record_user(uint16_t keycode, keyrecord_t *record) {
if(keycode == KC_A){
if(record->event.pressed) {
bool numlock_enabled = host_keyboard_led_state().num_lock;
if (!numlock_enabled) {
register_code(KC_NUMLOCK);
unregister_code(KC_NUMLOCK);
}
register_code(KC_LALT);
tap_code(KC_KP_0);
tap_code(KC_KP_1);
tap_code(KC_KP_9);
tap_code(KC_KP_8);
unregister_code(KC_LALT);
if (!numlock_enabled) {
register_code(KC_NUMLOCK);
unregister_code(KC_NUMLOCK);
}
}
target_skipped = true;
}
if(keycode == KC_S){
if(record->event.pressed) {
bool numlock_enabled = host_keyboard_led_state().num_lock;
if (!numlock_enabled) {
register_code(KC_NUMLOCK);
unregister_code(KC_NUMLOCK);
}
register_code(KC_LALT);
tap_code(KC_KP_0);
tap_code(KC_KP_2);
tap_code(KC_KP_3);
tap_code(KC_KP_0);
unregister_code(KC_LALT);
if (!numlock_enabled) {
register_code(KC_NUMLOCK);
unregister_code(KC_NUMLOCK);
}
}
target_skipped = true;
}

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